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3x^+2x^2=10.8
We move all terms to the left:
3x^+2x^2-(10.8)=0
We add all the numbers together, and all the variables
2x^2+3x-10.8=0
a = 2; b = 3; c = -10.8;
Δ = b2-4ac
Δ = 32-4·2·(-10.8)
Δ = 95.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{95.4}}{2*2}=\frac{-3-\sqrt{95.4}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{95.4}}{2*2}=\frac{-3+\sqrt{95.4}}{4} $
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